SUMMARY:Re: su - user -c "cd $VARIABLE;find . -name sri" doesn't work.

Thank you everyone who replied this. But only this
worked which is suggested  by Mark.Thank you Mark.

If you want "$VARIABLE" to come from the environment
of "user" you must 
escape the dollar sign so your shell will ignore it. 
There are several 
ways but this should work:

su - user  -c "cd \$VARIABLE;find . -name sri"

Hope this helps (and I hope that I haven't
misunderstood your 
problem...).



Sree.


Hi Gurus,
> 
> su - user  -c "cd $VARIABLE;find . -name sri"
> doesn't
> work.
> 
>     I read the previous messages in the forum but
> could not get it to work. The script is finding
> files
> in user_home instead in a specified path where I
> want
> to run. Making this work is of great improtance to
> me.The script which will invoke the above command is
> run in cron as root. I read shell wrappers could be
> used but I am not sure. If so please point me to
> link
> where I can delve into it.
> 
> Thank you,
> Sree.



		
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